/*实验2.6:求集合(有序单链表表示)的并、交和差运算*/
#include
#include
using namespace std;
typedef char ElemType;
typedef struct LNode
{ElemType data;struct LNode *next;
}LinkList;
void DisplayList(LinkList *L)
{LinkList *p = L->next;while(p != NULL){cout << p->data <<" ";p = p->next;}cout << endl;
}
void CreateListR(LinkList *L,ElemType a[],int n)
{LinkList *s,*r;int i;L=(LinkList *)malloc(sizeof(LinkList));L->next=NULL;r=L;for(i=0;idata=a[i];r->next=s;r=s;}r->next=NULL;
}
void Sort(LinkList *&head)
{LinkList *p=head->next,*q,*r;if(p!=NULL){r=p->next;p->next=NULL;p=r;while(p!=NULL){r=p->next;q=head;while(q->next!=NULL && q->next->data < p->data)q=q->next;p->next=q->next;q->next=p;p=r;}}
}
void Union(LinkList *ha,LinkList *hb,LinkList *&hc) //求两个集合的并
{LinkList *pa=ha->next,*pb=hb->next,*s,*tc;hc=(LinkList *)malloc(sizeof(LinkList));tc=hc;while(pa!=NULL&&pb!=NULL){if(pa->data < pb->data){s=(LinkList *)malloc(sizeof(LinkList));s->data=pa->data;tc->next=s;tc=s;pa=pa->next;}else if(pa->data > pb->data){s=(LinkList *)malloc(sizeof(LinkList));s->data=pb->data;tc->next=s;tc=s;pb=pb->next;}else{s=(LinkList *)malloc(sizeof(LinkList));s->data=pa->data;tc->next=s;tc=s;pa=pa->next;pb=pb->next;}}if(pb!=NULL)pa=pb;while(pa!=NULL){s=(LinkList *)malloc(sizeof(LinkList));s->data=pa->data;tc->next=s;tc=s;pa=pa->next;}tc->next=NULL;
}
void InterList(LinkList *ha,LinkList *hb,LinkList *&hc)
{LinkList *pa=ha->next,*pb,*s,*tc;hc=(LinkList *)malloc(sizeof(LinkList));tc=hc;while(pa!=NULL){pb=hb->next;while(pb!=NULL&&pb->data < pa->data)pb=pb->next;if(pb!=NULL&&pb->data==pa->data){s=(LinkList *)malloc(sizeof(LinkList));s->data=pa->data;tc->next=s;tc=s;}pa=pa->next;}tc->next=NULL;
}
void Subs(LinkList *ha,LinkList *hb,LinkList *&hc)
{LinkList *pa=ha->next,*pb,*s,*tc;hc=(LinkList *)malloc(sizeof(LinkList));tc=hc;while(pa!=NULL){pb=hb->next;while(pb!=NULL&&pb->data < pa->data)pb=pb->next;if(!(pb!=NULL&&pb->data==pa->data)){s=(LinkList *)malloc(sizeof(LinkList));s->data=pa->data;tc->next=s;tc=s;}pa=pa->next;}tc->next=NULL;
}
int main()
{LinkList *ha,*hb,*hc;ElemType a[]={'c','a','e','h'};ElemType b[]={'f','h','b','g','d','a'};CreateListR(ha,a,4);CreateListR(hb,b,6);cout << " 原集合A:
";//DisplayList(ha);cout << " 原集合B:";//DisplayList(hb);}