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Write a class StockSpanner
which collects daily price quotes for some stock, and returns the span of that stock's price for the current day.
The span of the stock's price today is defined as the maximum number of consecutive days (starting from today and going backwards) for which the price of the stock was less than or equal to today's price.
For example, if the price of a stock over the next 7 days were [100, 80, 60, 70, 60, 75, 85]
, then the stock spans would be [1, 1, 1, 2, 1, 4, 6]
.
Example 1:
Input: ["StockSpanner","next","next","next","next","next","next","next"], [[],[100],[80],[60],[70],[60],[75],[85]]
Output: [null,1,1,1,2,1,4,6]
Explanation:
First, S = StockSpanner() is initialized. Then:
S.next(100) is called and returns 1,
S.next(80) is called and returns 1,
S.next(60) is called and returns 1,
S.next(70) is called and returns 2,
S.next(60) is called and returns 1,
S.next(75) is called and returns 4,
S.next(85) is called and returns 6.Note that (for example) S.next(75) returned 4, because the last 4 prices
(including today's price of 75) were less than or equal to today's price.
Note:
- Calls to
StockSpanner.next(int price)
will have1 <= price <= 10^5
. - There will be at most
10000
calls toStockSpanner.next
per test case. - There will be at most
150000
calls toStockSpanner.next
across all test cases. - The total time limit for this problem has been reduced by 75% for C++, and 50% for all other languages.
编写一个 StockSpanner
类,它收集某些股票的每日报价,并返回该股票当日价格的跨度。
今天股票价格的跨度被定义为股票价格小于或等于今天价格的最大连续日数(从今天开始往回数,包括今天)。
例如,如果未来7天股票的价格是 [100, 80, 60, 70, 60, 75, 85]
,那么股票跨度将是 [1, 1, 1, 2, 1, 4, 6]
。
示例:
输入:["StockSpanner","next","next","next","next","next","next","next"], [[],[100],[80],[60],[70],[60],[75],[85]] 输出:[null,1,1,1,2,1,4,6] 解释: 首先,初始化 S = StockSpanner(),然后: S.next(100) 被调用并返回 1, S.next(80) 被调用并返回 1, S.next(60) 被调用并返回 1, S.next(70) 被调用并返回 2, S.next(60) 被调用并返回 1, S.next(75) 被调用并返回 4, S.next(85) 被调用并返回 6。注意 (例如) S.next(75) 返回 4,因为截至今天的最后 4 个价格 (包括今天的价格 75) 小于或等于今天的价格。
提示:
- 调用
StockSpanner.next(int price)
时,将有1 <= price <= 10^5
。 - 每个测试用例最多可以调用
10000
次StockSpanner.next
。 - 在所有测试用例中,最多调用
150000
次StockSpanner.next
。 - 此问题的总时间限制减少了 50%。
1 class StockSpanner { 2 var spans:[Int] 3 var prices:[Int] 4 var index:Int 5 6 init() { 7 spans = [Int](repeating:0,count:10_000) 8 prices = [Int](repeating:0,count:10000) 9 index = -1 10 } 11 12 func next(_ price: Int) -> Int { 13 index += 1 14 prices[index] = price 15 if index == 0 || price < prices[index - 1] 16 { 17 spans[index] = 1 18 return 1 19 } 20 var previousIndex:Int = index - 1 21 var span:Int = 1 22 while (previousIndex >= 0 && price >= prices[previousIndex]) 23 { 24 span += spans[previousIndex] 25 previousIndex -= spans[previousIndex] 26 } 27 spans[index] = span 28 return span 29 } 30 } 31 32 /** 33 * Your StockSpanner object will be instantiated and called as such: 34 * let obj = StockSpanner() 35 * let ret_1: Int = obj.next(price) 36 */
892ms
1 class StockSpanner { 2 3 private var s = [(Int, Int)]() 4 init() { 5 6 } 7 8 func next(_ price: Int) -> Int { 9 var sum = 1 10 while !s.isEmpty, s.last!.0 <= price { 11 sum += s.removeLast().1 12 } 13 s.append((price, sum)) 14 return sum 15 } 16 }
928ms
1 class StockSpanner { 2 3 init() { 4 5 } 6 7 struct PriceSpan { 8 let price: Int 9 let span: Int 10 } 11 12 var stack = [PriceSpan]() 13 14 func next(_ price: Int) -> Int { 15 guard stack.count > 0 else { 16 stack.append(PriceSpan(price: price, span: 1)) 17 return 1 18 } 19 20 var span = 1 21 while stack.last != nil && stack.last!.price <= price { 22 span += stack.last!.span 23 stack.removeLast() 24 } 25 26 stack.append(PriceSpan(price: price, span: span)) 27 return span 28 } 29 } 30 31 /** 32 * Your StockSpanner object will be instantiated and called as such: 33 * let obj = StockSpanner() 34 * let ret_1: Int = obj.next(price) 35 */
1036ms
1 class StockSpanner { 2 private var span: [Int] = [] 3 private var stack: [StockSpan] = [] 4 init() { 5 6 } 7 8 func next(_ price: Int) -> Int { 9 var stockSpan = StockSpan(price:price, span: 1) 10 while !stack.isEmpty && stack.last!.price <= stockSpan.price { 11 let removed = stack.removeLast() 12 stockSpan.span += removed.span 13 } 14 stack.append(stockSpan) 15 return stockSpan.span 16 } 17 18 struct StockSpan { 19 let price: Int 20 var span: Int 21 } 22 } 23 24 /** 25 * Your StockSpanner object will be instantiated and called as such: 26 * let obj = StockSpanner() 27 * let ret_1: Int = obj.next(price) 28 */
20764 kb
1 class StockSpanner { 2 var prices: [Int] = [] 3 var days: [Int] = [] 4 init() { 5 6 } 7 8 func next(_ price: Int) -> Int { 9 if prices.isEmpty || prices.last! > price { 10 prices.append(price) 11 days.append(1) 12 return 1 13 } 14 var index = prices.count - 1 15 var res = 1 16 while index >= 0 && prices[index] <= price { 17 res += days[index] 18 index -= days[index] 19 } 20 prices.append(price) 21 days.append(res) 22 return res 23 } 24 } 25 26 /** 27 * Your StockSpanner object will be instantiated and called as such: 28 * let obj = StockSpanner() 29 * let ret_1: Int = obj.next(price) 30 */
20820 kb
1 class StockSpanner { 2 3 private var elements : [(price : Int, conquered : Int)] = [] 4 init() { 5 6 } 7 8 func next(_ price: Int) -> Int { 9 var conquered : Int = 1 10 while !elements.isEmpty && elements.last!.price <= price { 11 let removed = elements.removeLast() 12 conquered += removed.conquered 13 } 14 15 elements.append((price: price, conquered: conquered)) 16 return elements.last!.conquered 17 } 18 } 19 20 /** 21 * Your StockSpanner object will be instantiated and called as such: 22 * let obj = StockSpanner() 23 * let ret_1: Int = obj.next(price) 24 */