百度笔试题

下面是百度的编程笔试题：输入a,b,n三个整数，a、b的取值范围是在0-9之间，n的取值范围是在1-10**9，让求得（a**n）*b的值的数字的和。

"""
思路：
1、让用户输入a,b,n
2、判断a,b是否为整数，并且是否在0-9之间，判断n是否为整数，并且是否在1-10**9
3、计算(a**n)*b的值
4、对求得值进行切分并相加
"""
"""
#  1、让用户输入a,b,n
while True:int_a = 0int_b = 0int_n = 0data_sum = 0try:int_a = int(input("请输入（0-9）之间的整数a："))int_b = int(input("请输入（0-9）之间的整数b："))int_n = int(input("请输入（1-10的9次方）之间的整数n："))except:print("您输入的数值中包含非整数值！！！")continue# 2、判断a,b是否为整数，并且是否在0-9之间，判断n是否为整数，并且是否在1-10**9if (0 <= int_a <= 9) & (0 <= int_b <= 9) & (1 <= int_n <= (10**9)):#  3、计算(a ** n) * b的值superdata = str((int_a**int_n) * int_b)print("superdata=", superdata)#  4、对求得值进行切分并相加for data in superdata:data_sum = data_sum + int(data)print("data_sum:", data_sum)print("最终data_sum = ", data_sum)else:print("您输入的值超过了所要求的整数范围！！！")
"""
import timea = 3
b = 4
n = 3def sum_superdata(a, b, n):data_sum = 0try:int_a = int(a)int_b = int(b)int_n = int(n)except:print("您输入的数值中包含非整数值！！！")if (0 <= int_a <= 9) & (0 <= int_b <= 9) & (1 <= int_n <= (10 ** 9)):superdata = str((int_a ** int_n) * int_b)print("superdata=", superdata)for data in superdata:data_sum = data_sum + int(data)print("data_sum:", data_sum)print("最终data_sum = ", data_sum)else:print("您输入的值超过了所要求的整数范围！！！")# sum_superdata(1, 9, 100)if __name__ == "__main__":start = time.time()sum_superdata(a, b, n)end_start = time.time()print("sum_time = ", format(end_start-start))